Question
Question: A light weight boy holds two heavy dumbbells of equal masses with outstretched arms while standing o...
A light weight boy holds two heavy dumbbells of equal masses with outstretched arms while standing on a turn-table which is rotating with an angular frequency ω1 when the dumbbells are at distance r1 from the axis of rotation. The boy suddenly pulls the dumbbells towards his chest until they are at distance r2 from the axis of rotation. The new angular frequency of rotation ω2 of the turn-table will be equal to
A. ω1r1r2
B. ω1r22r12
C. ω1r2r1
D. ω1r12r22
Solution
In order to solve this question we need to understand conservation of angular momentum and energy. Angular momentum is defined as momentum in rotation and it is the quantity of rotation of the body and it is mathematically defined as the product of moment of inertia and its angular velocity. Angular momentum is conserved and torque is defined as the space derivative of angular momentum, so if a torque during rotation is zero then the space derivative of angular momentum is zero and hence angular momentum is constant or conserved during rotation.
Complete step by step answer:
Mathematically angular momentum is defined as, J=Iω.
Here, I is the moment of inertia and it is defined as I=mr2.
So when dumbbells are far away from his chest then angular momentum is,
J1=mr12ω1
Here, r1 is radius and ω1 is angular frequency.
Similarly angular momentum when dumbbells are close to his chest is given by,
J2=mr22ω2
Here, r2 is radius and ω2 is angular frequency
Since angular momentum is conserved so J1=J2.
Putting values we get,
mr12ω1=mr22ω2
⇒r12ω1=r22ω2
∴ω2=ω1r22r12
So the correct option is B.
Note: It should be remembered that, Due to law of conservation of angular momentum when the distance from axis of rotation gets decreased it increases the angular velocity of the body that’s why when a dumbbells are far away from chest angular velocity is less as compared to when dumbbells are closed to chest.