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Question

Question: A light string passing over a smooth light pulley connects two blocks of masses \(m _ { 1 }\) and ...

A light string passing over a smooth light pulley connects two blocks of masses m1m _ { 1 } and m2m _ { 2 } (vertically). If the acceleration of the system is g/8 then the ratio of the masses is

A

8 : 1

B

9 : 7

C

4 : 3

D

5 : 3

Answer

9 : 7

Explanation

Solution

a=(m2m1m1+m2)ga = \left( \frac { m _ { 2 } - m _ { 1 } } { m _ { 1 } + m _ { 2 } } \right) g = g8\frac { g } { 8 } ; by solving m2m1=9/7\frac { m _ { 2 } } { m _ { 1 } } = 9 / 7