Question

A light rod with uniform cross-section of $4 \times 10 ^ { 10 } \mathrm {~N} / \mathrm { m } ^ { 2 }$ and $1 \times 10 ^ { 10 } \mathrm {~N} / \mathrm { m } ^ { 2 }$ respectively. The displacement of point B will be

• A.
• B.
• C.
• D.

Answer 1

Answer: (C)

Answer 2

Increment in the length

AB = $\frac { M g L } { A Y } = \frac { 10 \times 10 \times 0.1 } { 10 ^ { - 4 } \times 2.5 \times 10 ^ { 10 } } = 4 \times 10 ^ { - 6 } \mathrm {~m}$

$\therefore$Displacement of point B =