Question

A light ray is incident on a glass slab of thickness $4\sqrt{3}$ cm and refractive index $\sqrt{2}$. The angle of incidence is equal to the critical angle for the glass slab with air. The lateral displacement of the ray after passing through the glass slab is _____ cm.
(Given $\sin 15^\circ = 0.25$)

Answer 1

1. Calculate Total Mass of Reactants ($m_r$):
$m_r = 235.0439 \, \text{u}.$
**2. Calculate Total Mass of Products ($m_p$): **
$m_p = 139.9054 + 93.9063 + 1.0086 = 234.8203 \, \text{u}.$
**3. Calculate Disintegration Energy ($Q$): **
The disintegration energy $Q$ is given by:
$Q = (m_r - m_p)c^2.$
Substitute the values:
$Q = (235.0439 - 234.8203) \times 931.$
Simplify:
$Q = 0.2236 \times 931 = 208.1716 \, \text{MeV}.$
Answer: $208 \, \text{MeV}$