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Physics Question on Refraction Through A Prism

A light ray enters through a right angled prism at point P with the angle of incidence 30° as shown in figure. It travels through the prism parallel to its base BC and emerges along the face AC. The refractive index of the prism is :
a right angled prism at point P with the angle of incidence

A

54\frac{\sqrt5}{4}

B

52\frac{\sqrt5}{2}

C

34\frac{\sqrt3}{4}

D

32\frac{\sqrt3}{2}

Answer

52\frac{\sqrt5}{2}

Explanation

Solution

Applying Snell's law at point P:
n=sin⁡isin⁡r=sin⁡30∘sin⁡18.43∘=0.50.276=52.n = \frac{\sin i}{\sin r} = \frac{\sin 30^\circ}{\sin 18.43^\circ} = \frac{0.5}{0.276} = \frac{\sqrt{5}}{2}.