Question

A lift is moving down with acceleration a. A man in the lift drops a ball inside the lift. The acceleration of the ball as observed by the man in the lift and a man standing stationary on the ground are respectively

• A. $g , g$
• B. $g - a , g - a$
• C. $g - a , g$
• D. $a , g$

Answer 1

Answer: (C)

$g - a , g$

Answer 2

Due to relative motion, acceleration of ball observed by observer in lift = (g – a) and for man on earth the acceleration remains g.