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Question: A large open tank has two holes in the wall. One is a square hole of side L at a depth y from the to...

A large open tank has two holes in the wall. One is a square hole of side L at a depth y from the top and the other is a circular hole of radius R at a depth 4y from the top. When the tank is completely filled with water the quantities of water flowing out per second from both the holes are the same. Then R is equal to

A

2πL2 \pi L

B

L2π\frac { L } { \sqrt { 2 \pi } }

C

L

D

L2π\frac { L } { 2 \pi }

Answer

L2π\frac { L } { \sqrt { 2 \pi } }

Explanation

Solution

Velocity of efflux when the hole is at depth h, v=2ghv = \sqrt { 2 g h }

Rate of flow of water from square hole L22gyL ^ { 2 } \sqrt { 2 g y }

Rate of flow of water from circular hole

Q2=a2v2Q _ { 2 } = a _ { 2 } v _ { 2 }= πR22g(4y)\pi R ^ { 2 } \sqrt { 2 g ( 4 y ) }

and according to problem Q1=Q2Q _ { 1 } = Q _ { 2 }

L22gy=πR22g(4y)L ^ { 2 } \sqrt { 2 g y } = \pi R ^ { 2 } \sqrt { 2 g ( 4 y ) } R=L2πR = \frac { L } { \sqrt { 2 \pi } }