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Question: A large number of particles are moving with same magnitude of velocity v but having random direction...

A large number of particles are moving with same magnitude of velocity v but having random directions. The average relative velocity between any two particles averaged over all the paris is

A

π/4 v

B

π/2 v

C

3/π v

D

4/π v

Answer

4/π v

Explanation

Solution

Let α be the angle between velocities of a pair of particles, then relative velocity is given by

vr = v2+v22v×v×cosα\sqrt{v^{2} + v^{2} - 2v \times v \times \cos\alpha}

= 2v sin α/2 ( 1 – cos α = 2 sin2α/2)

Average relative velocity is given by

average vr = 02π2v(sinα/2)dα02πdα=4πv\int_{0}^{2\pi}\frac{2v\left( \sin\alpha/2 \right)d\alpha}{\int_{0}^{2\pi}{d\alpha}} = \frac{4}{\pi}v