Question

A large box is moving on horizontal floor with constant acceleration a = g. A particle is projected inside box with velocity u and angle 'q' with horizontal from box. frame. For the given 'u', the value of 'q' for which horizontal range inside box will be maximum is –

• A. $\frac{\pi}{4}$
• B. $\frac{\pi}{8}$
• C. $\frac{3\pi}{8}$
• D. $\frac{\pi}{3}$

Answer 1

Answer: (B)

$\frac{\pi}{8}$

Answer 2

T = $\frac { 2 \mathrm { u } \sin \theta } { \mathrm { g } }$

R = $\frac { u ^ { 2 } \sin 2 \theta } { \mathrm { g } }$ – $\frac { 2 \mathrm { u } ^ { 2 } \sin ^ { 2 } \theta } { \mathrm { g } }$

R will be max when $\frac { \mathrm { aR } } { \mathrm { d } }$ = 0

̃ q = $\frac { \pi } { 8 }$