Question
Question: A large bottle is fitted with a capillary tube at the bottom. The ratio of times taken to empty the ...
A large bottle is fitted with a capillary tube at the bottom. The ratio of times taken to empty the bottle when it is first filled with water and next with oil of relative density 0.8 is
[ηwater=10−3Pa−s,ηoil=2×10−3Pa−s]
A. 5:2
B. 2:3
C. 3:4
D. 1:2
Solution
The above problem can be resolved by knowing the mathematical formulation for the rate of flow of liquids through the vessel of desired length. Moreover, the time taken to pour out the liquid depends on the rate of flow of liquid from the vessel.
Complete step by step answer:
The ratio of the relative density is, ρ2:ρ1=0.8.
As, the ratio of time taken to empty the vessel is proportional to the discharge rates of different liquids. Then the expression is given as,
toiltwater=QoilQwater..........................(1)
And the formula for discharge rate for water is,
Qwater=8ηwater×Lπρ1(gh)r4.......................(2)
And the formula for discharge rate for oil is,
Qoil=8ηoil×Lπρ2(gh)r4.......................(3)
Here, r is the radius of tube, L is length of tube, h is the vertical height of tube and g is the gravitational acceleration.
Taking the ratio of equation 1 and 2 as,