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Question: A Kelvin thermometer and a Fahrenheit thermometer used to record temperature of melting metal, read ...

A Kelvin thermometer and a Fahrenheit thermometer used to record temperature of melting metal, read the same. What will a Celsius thermometer read at that temperature?
A. 301.25301.25℃
B. 273273℃
C. 457457℃
D. 760760℃

Explanation

Solution

We can use the concept of thermometers, given as tl.p.n=\dfrac{t-l.p.}{n}= constant. Where t is the temperature reading in the thermometer, l.p. is the lower point of that thermometer and n is the number of divisions in that thermometer. One should know to relate temperature on the thermometer with different degree readings.

Formula used:
K273100=F32180=C0100\dfrac{K-273}{100}=\dfrac{F-32}{180}=\dfrac{C-0}{100}

Complete step by step answer:
Let the temperature reading on the Kelvin thermometer and the Fahrenheit thermometer be xx. (The question says both thermometers have the same reading) We know that for any thermometertl.p.n=\dfrac{t-l.p.}{n}= constant. Where t is the temperature reading in the thermometer, l.p. is the lower point of that thermometer and n is the number of divisions in that thermometer.The relation between different thermometers is given by
K273100=F32180=C0100\dfrac{K-273}{100}=\dfrac{F-32}{180}=\dfrac{C-0}{100}.
Here K refers to the reading on the Kelvin scale, f refers to the reading on Fahrenheit scale and C refers to the reading on the Celsius scale.
From the first equality, by substituting the value of K and C=x=x, we get
\dfrac{x-273}{100}=\dfrac{x-32}{180} \\\ \Rightarrow 9\left( x-273 \right)=5\left( x-32 \right) \\\ \Rightarrow 9x-5x=2457-160 \\\ \Rightarrow 4x=2297 \\\ \Rightarrow x=\dfrac{2297}{4}=574.25 \\\
Therefore, the temperature on Fahrenheit thermometer and kelvin thermometer is 574.25℉/K. From the second equality we have,
\dfrac{F-32}{180}=\dfrac{C-0}{100} \\\ \Rightarrow \dfrac{574.25-32}{180}=\dfrac{C-0}{100} \\\ \therefore C=\dfrac{542.25\times 5}{9}=301.25 \\\
Therefore, the temperature on Celsius thermometer is 301.25 °C.Hence option A is correct.

Note: The most important point in this question is to remember the relation between thermometers with different scales K273100=F32180=C0100\dfrac{K-273}{100}=\dfrac{F-32}{180}=\dfrac{C-0}{100}. One should also remember the lower point and number of divisions on the thermometer of different scales.

ScaleLower pointNumber of divisions
Kelvin273100
Fahrenheit32180
Celsius0100