Question

A juggler throws balls into air. He throws one when ever the previous one is at its highest point. If he throws $n$ balls each second, the height to which each ball will rise is

• A. $\frac{g}{2n^{2}}$
• B. $\frac{2g}{n^{2}}$
• C. $\frac{2g}{n}$
• D. $\frac{g}{4n^{2}}$

Answer 1

Answer: (A)

$\frac{g}{2n^{2}}$

Answer 2

Time taken by each ball to reach highest point, $t=\frac{1}{n}$ second. As the juggler throws the second ball, when the first ball is at its highest point, so $v = 0$ Using $v = u + at$ , we have $0 = u + (- g) (1 /n)$ or $u = (g/n)$ . Also, $v^2 = u^2 + 2as$ $\therefore 0=\left(g/n^{2}\right)+2\left(-g\right)h$ or $h=\frac{g}{2n^{2}}$