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Physics Question on Electromagnetic induction

A jet plane of wing span 20 m20\, m is travelling towards west at a speed of 400 ms−1400 \,{ms^{-1}}. If the earth?s total magnetic field is 4×10−4T4 \times 10^{-4} T and the dip angle is 30∘30^\circ, at that place, the voltage difference developed across the ends of the wing is

A

1.6 V

B

3.2 V

C

0.8 V

D

6.4 V

Answer

1.6 V

Explanation

Solution

Given,
Speed (v)=400 ms−1(v)=400 \,ms ^{-1}
Magnetic field (B)=4×10−4 T(B)=4 \times 10^{-4} \,T
Dip angle θ−30∘\theta-30^{\circ}
We know that,
Voltage difference =Blv sin⁡ θ=Blv \,\sin \,\theta
=4×10−4×20×400×sin⁡30∘=4 \times 10^{-4} \times 20 \times 400 \times \sin 30^{\circ}
=32000×10−4×sin⁡30=32000 \times 10^{-4} \times \sin 30
=32000×10−4×12=1.6 V=32000 \times 10^{-4} \times \frac{1}{2}=1.6\, V