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Question

Physics Question on laws of motion

A jet of water with a cross-sectional area a is striking against a wall at an angle θ\theta to the horizontal and rebounds elastically. If the velocity of water jet is v and the density is ρ,\rho , the normal force acting on the wall is

A

2av2ρcosθ2av^{2}\rho \,\cos \theta

B

av2ρcosθav^{2}\rho \,\cos \theta

C

2avρcosθ2av\rho \,\cos \theta

D

avcosθav\,\cos \theta

Answer

2av2ρcosθ2av^{2}\rho \,\cos \theta

Explanation

Solution

The normal force acting on the wall == Rate of - change of momentum of water jet =mvcosθ(mvcosθ)=m v \cos \theta-(-m v \cos \theta) =2mvcosθ=2 m v \cos \theta =2=2 (volume ×\times density )vcosθ) v \cos \theta =2(avρ)vcosθ=2av2ρcosθ=2(a v \rho) v \cos \theta=2 a v^{2} \rho \cos \theta