Question

‘A’ is a carbide of ${3^{rd}}$ period element which forms amphoteric oxide in the below reaction. How D can be converted into B?

A. $Ni$
B. $Na/ether$
C. $Zn - Hg/HCl$
D. $LiAl{H_4}$

Answer 1

D can be converted to B by using the Clemmensen’s reduction. Clemmensen reduction is the reduction in which the reduction of aldehydes or ketones is done using zinc amalgam and concentrated hydrochloric acid.

Complete step by step answer:
From the question, it is given that A is carbide in the reaction.
When the hydrolysis of metal carbide is done it gives methane. So, the element B is methane.
As given in question A is the element in the third period. We know that there are eight elements in the third period which are – sodium, magnesium, aluminium, silicon, phosphorus, sulphur, chlorine and argon.
So, let's take aluminium from the third period then the carbide A will be aluminium carbide whose molecular formula is $A{l_4}{C_3}$. Then, the reaction is –
$A{l_4}{C_3}\xrightarrow{{{H_2}O}}C{H_4}$
When methane B is oxidized with $M{o_2}{O_3}$ at the temperature of ${500^ \circ }C$ results in the formation of formaldehyde D. Therefore, the reaction is –
$C{H_4}\xrightarrow{{M{o_2}{O_3}/{{500}^ \circ }C}}HCHO$
As for the conversion from B to D we need to oxidize the compound B. Therefore, for the conversion from D to B we need to reduce D to form B. Reduction is the reverse process of oxidation.
Hence, this reduction process is known as Clemmensen’s reduction which can be defined as the reduction process in which aldehyde and ketone are reduced to alkanes in the presence of zinc amalgam and concentrated hydrochloric acid. So, the Clemmensen’s reduction is –
$HCHO\xrightarrow{{Zn - Hg/HCl}}C{H_4}$
From the reaction we conclude thatD can be converted into B by $Zn - Hg/HCl$.
Hence, the elements in the reaction in question are –
A – Aluminium carbide, $A{l_4}{C_3}$
B – Methane, $C{H_4}$
D – Formaldehyde, $HCHO$

So, Option D is correct.

Note: The hydrocarbons can be formed by the various process –
Hydrogenation
Addition
Substitution
Reduction
Decarboxylation