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Question: A hypothetical reaction X2 + Y2\(\longrightarrow\) 2XY follows the mechanism given below. X2 X + X ...

A hypothetical reaction X2 + Y2\longrightarrow 2XY follows the mechanism given below.

X2 X + X \rightleftharpoons [Fast]

X + Y2\longrightarrow XY + Y [Slow]

X + Y \longrightarrowXY [Fast]

The order of overall reaction is

A

2

B

1

C

1.5

D

Zero

Answer

1.5

Explanation

Solution

Rate = K [X][Y2]\text{Rate = K }\lbrack X\rbrack\lbrack Y_{2}\rbrack

Keq=[X]2[X2]K_{eq} = \frac{\lbrack X\rbrack^{2}}{\left\lbrack X_{2} \right\rbrack}

[X]=Keq×[X2]1/2\lbrack X\rbrack = \sqrt{K_{eq}} \times \left\lbrack X_{2} \right\rbrack^{1/2}

Rate = K× Keq[X2]1/2 [Y2]K \times \ \sqrt{K_{\text{eq}}}\lbrack X_{2}\rbrack_{\text{1/2}}\ \lbrack Y_{2}\rbrack

So the order of overall reaction is 1.5

Keq=[X]2[X2a]K_{eq} = \frac{\lbrack X\rbrack^{2}}{\left\lbrack X2_{a} \right\rbrack}

[X] =Keq[X2]1/2\lbrack X\rbrack\text{ =}\sqrt{K_{\text{eq}}}\lbrack X_{2}\rbrack^{\text{1/2}}