Question

A hypothetical electromagnetic wave is show below. The frequency of the wave is x × 1019 Hz. x = ______ (nearest integer)

Answer 1

Given:
$\lambda = 1.5 \times 4 \, \text{pm} = 6 \times 10^{-12} \, \text{meter}.$
Using the relationship:
$\lambda \nu = c,$
where $c = 3 \times 10^8 \, \text{m/s}$, we can find $\nu$ as:
$6 \times 10^{-12} \cdot \nu = 3 \times 10^8$
$\nu = \frac{3 \times 10^8}{6 \times 10^{-12}} = 5 \times 10^{19} \, \text{Hz}.$
Therefore, $x = 5$.

Answer 2

Given:
$\lambda = 1.5 \times 4 \, \text{pm} = 6 \times 10^{-12} \, \text{meter}.$
Using the relationship:
$\lambda \nu = c,$
where $c = 3 \times 10^8 \, \text{m/s}$, we can find $\nu$ as:
$6 \times 10^{-12} \cdot \nu = 3 \times 10^8$
$\nu = \frac{3 \times 10^8}{6 \times 10^{-12}} = 5 \times 10^{19} \, \text{Hz}.$
Therefore, $x = 5$.