Question

A hydrogen atom (ionisation potential 13.6 eV) makes a transition from third excited state to first excited state. The energy of the photon emitted in the process is.

• A. 1.89 eV
• B. 2.55 eV
• C. 12.09 eV
• D. 12.75 eV

Answer 1

Answer: (B)

2.55 eV

Answer 2

Energy released

$= 13.6\left\lbrack \frac{1}{(2)^{2}} - \frac{1}{(4)^{2}} \right\rbrack = 2.55eV$.