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Question: A hydrogen atom in ground state absorbs 10.2 eV of energy. The orbital angular momentum of the elect...

A hydrogen atom in ground state absorbs 10.2 eV of energy. The orbital angular momentum of the electron is increased by-

A

1.05 × 10–34Js

B

2.11 × 10–34Js

C

3.16 × 10–34Js

D

4.22 × 10–34Js

Answer

1.05 × 10–34Js

Explanation

Solution

DE = E2 – E1 = 10.2eV = –3.4eV + 13.6eV

so, n2 = 2 & n1 = 1

DL = 2h2πh2π=h2π=6.63×10342×3.14\frac{2h}{2\pi}–\frac{h}{2\pi} = \frac{h}{2\pi} = \frac{6.63 \times 10^{–34}}{2 \times 3.14}J.s

= 1.05 × 10–34J.s