Question
Question: A horizontal force of \[1.2\;{\rm{kg}} \cdot {\rm{wt}}\] is applied to a \[1.5\;{\rm{kg}}\]block res...
A horizontal force of 1.2kg⋅wt is applied to a 1.5kgblock resting on a horizontal surface. If μ=0.3. Find the acceleration produced in the block.
Solution
The above problem can be resolved by using the concept and the fundamentals of the frictional force and the net force acting on the horizontal surface. When an object is moving in a horizontal plane, such that there is some friction between the surface and object, then net force is given by taking the difference between horizontal force and frictional force. Then we can substitute the values of gravitational acceleration and other variables like the mass of the block, producing the acceleration of the block.
Complete step by step answer:
Given:
The mass on which the horizontal force is acting is, M=1.2kg⋅wt.
The mass of the block is, m=1.5kg.
The coefficient of friction is, μ=0.3.
The magnitude of horizontal force is given as
FH=M×g……………………………………………….. (1)
Here, g is the gravitational acceleration and its value is 9.8m/s2.
The magnitude of frictional force is,
Ff=μmg…………………………………………… (2)
Now using the equation 1 and 2, the acceleration produced in the block is,