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Question

Physics Question on Friction

A horizontal force 10 N is applied to a block 4 as shown in figure. The mass of blocks A and B are 2 kg and 3 kg, respectively. The blocks slide over a frictionless surface. The force exerted by block A on block B is:

A

Zero

B

4N4N

C

6N6N

D

10N10N

Answer

6N6N

Explanation

Solution

The total acceleration of the system is:
a=FmA+mB=102+3=2m/s2a = \frac{F}{m_A + m_B} = \frac{10}{2 + 3} = 2 \, m/s^2.
The force exerted by A on B is:
FAB=mBa=3×2=6NF_{AB} = m_B \cdot a = 3 \times 2 = 6 \, N.