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Question: A hollow vertical cylinder of radius r and height h has a smooth internal surface. A small particle ...

A hollow vertical cylinder of radius r and height h has a smooth internal surface. A small particle is placed in contact with the inner side of the upper rim, at point A, and given a horizontal speed u, tangential to the rim. It leaves the lower rim at point B, vertically below A. If n is an integer then-

A

u2πr2h/g\frac{u}{2\pi r}\sqrt{2h/g} = n

B

h2πr\frac{h}{2\pi r} = n

C

2πrh\frac{2\pi r}{h} = n

D

u2gh\frac{u}{\sqrt{2gh}} = n

Answer

u2πr2h/g\frac{u}{2\pi r}\sqrt{2h/g} = n

Explanation

Solution

Time taken in falling = 2hg\sqrt { \frac { 2 h } { g } }

Distance moved in horizontal plane

= u2hh=n.2πru \cdot \sqrt { \frac { 2 h } { h } } = n .2 \pi r