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Question: A hollow sphere of volume V is floating on water surface with half immersed in it. What should be th...

A hollow sphere of volume V is floating on water surface with half immersed in it. What should be the minimum volume of water poured inside the sphere so that the sphere now sinks into the water

A

V/2V / 2

B

C

V/4V / 4

D

V

Answer

V/2V / 2

Explanation

Solution

When body (sphere) is half immersed, then

upthrust = weight of sphere

When body (sphere) is fully immersed then,

Upthrust = wt. of sphere + wt. of water poured in sphere

V×ρliq ×g=V×ρ×g+V×ρliq ×gV \times \rho _ { \text {liq } } \times g = V \times \rho \times g + V ^ { \prime } \times \rho _ { \text {liq } } \times g

V=V2V ^ { \prime } = \frac { V } { 2 }