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Question: A hollow sphere of mass 4 m is placed as shown in figure and two point mass m are fixed to it at poi...

A hollow sphere of mass 4 m is placed as shown in figure and two point mass m are fixed to it at point P and Q. The position of CM of the system is –

A

(0,R2)\left( 0, - \frac{R}{2} \right)

B

(0,R3)\left( 0, - \frac{R}{3} \right)

C

(0,2R3)\left( 0, - \frac{2R}{3} \right)

D

(0,R4)\left( 0, - \frac{R}{4} \right)

Answer

(0,R3)\left( 0, - \frac{R}{3} \right)

Explanation

Solution

Xcm = mRmR6m\frac{mR - mR}{6m} = 0

Ycm = 4m×(R2)6m\frac{4m \times \left( \frac{- R}{2} \right)}{6m} = – R/3