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Question

Question: A hollow sphere of diameter 0.2 m and mass 2 kg is rolling on an inclined plane with velocity v = 0....

A hollow sphere of diameter 0.2 m and mass 2 kg is rolling on an inclined plane with velocity v = 0.5 m/s. The kinetic energy of the sphere is:

A

0.1 J

B

0.3 J

C

0.5 J

D

0.42 J.

Answer

0.42 J.

Explanation

Solution

KN=12mv2(K2R2+1)=12×2×(0.5)2×(23+1)=0.42 J\mathrm { K } _ { \mathrm { N } } = \frac { 1 } { 2 } \mathrm { mv } ^ { 2 } \left( \frac { \mathrm { K } ^ { 2 } } { \mathrm { R } ^ { 2 } } + 1 \right) = \frac { 1 } { 2 } \times 2 \times ( 0.5 ) ^ { 2 } \times \left( \frac { 2 } { 3 } + 1 \right) = 0.42 \mathrm {~J}