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Question

Physics Question on electrostatic potential and capacitance

A hollow metallic surface of radius 10 cm10\, cm is given a charge of 3.2×10−193.2\times10^{-19} coulomb. The electric potential at a point 4 cm4\,cm from the centre is

A

9×10−99\times10^{-9}volt

B

288×10−9288\times10^{-9}volt

C

28.8×10−928.8\times10^{-9}volt

D

zero

Answer

28.8×10−928.8\times10^{-9}volt

Explanation

Solution

The electric potential inside the sphere is same as that on its surface. Hence V=14 π ε0×3.2×10−19(0.1)=9×109×3.2×10−190.1=28.8×10−19V= \frac{1}{4 \, \pi \, \varepsilon_0} \times \frac{3.2 \times 10^{-19}}{(0.1)} = \frac{9 \times 10^9 \times 3.2 \times 10^{-19}}{0.1} = 28.8 \times 10^{-19} V = 28.8×10−928.8 \times 10^{-9} V.