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Question

Physics Question on Electric Current

A hollow cylindrical conductor has length of 314m314\, m, while its inner and outer diameters are 4mm4 \, mm and 8mm8 \, mm respectively The resistance of the conductor is n×103Ωn \times 10^{-3} \Omega.If the resistivity of the material is 24×108Ωm24 \times 10^{-8} \Omega m The value of nn is ___

Answer

The correct answer is 2.
R=ρAℓ​, the cross-sectional area is π(b2−a2)
R=ρπ(b2−a2)ℓ​=3.14×(42−22)×10−62.4×10−8×3.14​
=2×10−3Ω
\therefore n=2