Solveeit Logo

Question

Question: A hollow cylinder with both sides open generates a frequency of \[f\]in air. When cylinder verticall...

A hollow cylinder with both sides open generates a frequency of ffin air. When cylinder vertically immersed into water by half its length then frequency will be
a) ff
b) 2f2f
c) f2\dfrac{f}{2}
d) f4\dfrac{f}{4}

Explanation

Solution

Since here it is not given which mode it is talking of so we will take default or fundamental frequency for the open hollow cylinders.

Formula Used:
1.Fundamental frequency of pipe which has both ends open: f=v2Lf = \dfrac{v}{{2L}} …… (A)
Where, vvis the velocity of sound in air and LLis length of air column in the pipe.
2. Fundamental frequency of pipe which has just one of the ends open: f1=v4L{f_1} = \dfrac{v}{{4L}}
Where, vvis velocity of sound in air and LLis length of air column in the pipe.
3. Nearest distance between antinode and node: λ4\dfrac{\lambda }{4} …… (B)
Where, λ\lambda is the wavelength of sound.
4. Relation between speed, wavelength and frequency of sound: f=vλf = \dfrac{v}{\lambda } …… (C)

Complete step by step answer:
Given, just fundamental frequency of hollow cylinder both ends open: ff
Let say, vv be the velocity of sound in air and L be the length of pipe or cylinder.
fnew{f_{new}} be a new frequency when half immersed in water.
Diagram: Below would show fundamental mode setup in two cases:

Step 1:
Open end of the pipe acts as an antinode and the closed end as a node.
Case 1: Both ends open
Therefore, in case of both ends open:
λ4+λ4=L\dfrac{\lambda }{4} + \dfrac{\lambda }{4} = L
λ2=Lλ=2L\Rightarrow \dfrac{\lambda }{2} = L \Rightarrow \lambda = 2L …… (1)
From equation (c) and (1)
We get fundamental frequency to be: f = \dfrac{v}{\lambda }$$$$ \Rightarrow f = \dfrac{v}{{2L}} …… (2)
Step 2:
Case 2: One end closed:
Here, Water boundaries act as nodes and open-end act as antinodes. And the length of the air column reduces to L2\dfrac{L}{2}.
Distance between antinode to node: λ14=L2\dfrac{{{\lambda _1}}}{4} = \dfrac{L}{2} …… (3)
Using equation (C) and (3) we get new frequency to be: f1=vλf1=v2L \Rightarrow {f_1} = \dfrac{v}{\lambda } \Rightarrow {f_1} = \dfrac{v}{{2L}} …… (4)
Step 3:
Comparing equation (2) and (4) we get: f=f1=v2L \Rightarrow f = {f_1} = \dfrac{v}{{2L}}
Correct Answer:
Option : a)ff

Note:
1. Velocity of sound is constant in a given isotropic media.
2. The first fundamental mode is the longest wavelength possible for the standing wave that can be setup in a given air column.