Question

A hollow cylinder has a charge q coulomb within it. If f is the electric flux in units of voltmeter associated with the curved surface B, the flux linked with the plane surface A in units of voltmeter will be-

• A. $\frac{q}{2\varepsilon_{0}}$
• B. $\frac{\varphi}{3}$
• C. $\frac{q}{\varepsilon_{0}}$ – f
• D. $\frac { 1 } { 2 }$ $\left( \frac{q}{\varepsilon_{0}}–\varphi \right)$

Answer 1

Answer: (D)

\frac { 1 } { 2 }$$\left( \frac{q}{\varepsilon_{0}}–\varphi \right)

Answer 2

f_A + f_C + f_B = $\frac { \mathrm { q } } { \epsilon _ { 0 } }$

Q f_A = f_C

\ f_A + f_A + f = $\frac { \mathrm { q } } { \epsilon _ { 0 } }$

\ $\phi _ { \mathrm { A } } = \frac { 1 } { 2 } \left( \frac { \mathrm { q } } { \epsilon _ { 0 } } - \phi \right)$