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Question

Physics Question on electrostatic potential and capacitance

A hollow cylinder has a charge qq coulomb within it. If ϕ\phi is the electric flux in units of voltmeter associated with the curved surface BB, the flux linked with the plane surface AA in units of voltmeter will be-

A

q2ϵ0\frac{ q }{2 \epsilon_{0}}

B

ϕ3\frac{\phi}{3}

C

qϵ0ϕ\frac{ q }{\epsilon_{0}}-\phi

D

12(qϵ0ϕ)\frac{1}{2}\left(\frac{ q }{\epsilon_{0}}-\phi\right)

Answer

12(qϵ0ϕ)\frac{1}{2}\left(\frac{ q }{\epsilon_{0}}-\phi\right)

Explanation

Solution

ϕtotal =ϕcurved +ϕplane surfaces =qϵ0\phi_{\text {total }}=\phi_{\text {curved }}+\phi_{\text {plane surfaces }}=\frac{ q }{\epsilon_{0}}
ϕ+2ϕAqϵ0\phi+2 \phi_{ A }-\frac{ q }{\epsilon_{0}}
ϕA12(qϵ0ϕ)\Rightarrow \phi_{ A }-\frac{1}{2}\left(\frac{ q }{\epsilon_{0}}-\phi\right)