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Question: A hockey ball of mass 200 g travelling at \(10m{s^{ - 1}}\) is struck by a hockey stick so as to ret...

A hockey ball of mass 200 g travelling at 10ms110m{s^{ - 1}} is struck by a hockey stick so as to return it along its original path with a velocity of5ms15m{s^{ - 1}}. Calculate the change of momentum which occurred in the motion of the hockey ball by the force applied by the hockey stick:
A) -3 Ns.
B) 3 Ns.
C) 6 Ns.
D) -6 Ns.

Explanation

Solution

Momentum is defined as the product of mass and velocity. The rate of change of momentum with respect to time is known as force. The force is defined as the product of mass and acceleration of the body and unit of force is Newtons.

Formula Used: The formula of momentum is given by,
p=mv\Rightarrow p = m \cdot v
Where p is the momentum the mass is m and the velocity is v.

Complete step by step answer:
It is given in the problem that a hockey ball of mass 200 g travelling at 10ms110m{s^{ - 1}} is struck by a hockey stick so as to return it along its original path with a velocity of 5ms15m{s^{ - 1}} and we need to calculate the change in the momentum of the hockey ball.
The formula of momentum is given by,
p=mv\Rightarrow p = m \cdot v
Where p is the momentum the mass is m and the velocity is v.
The mass of the hockey ball is 200 g and the initial velocity of the ball is 10ms110m{s^{ - 1}} and the final velocity of the ball is 5ms15m{s^{ - 1}} in the opposite direction of the initial direction. The change in the momentum is given by,
Δp=m(vu)\Delta p = m\left( {v - u} \right)
Where Δp\Delta p is change in momentum mass is m initial and final velocity of the hockey ball is u and v respectively.
The change in momentum of hockey ball is equal to,
Δp=m(vu)\Rightarrow \Delta p = m\left( {v - u} \right)
Δp=(2001000)[5(10)]\Rightarrow \Delta p = \left( {\dfrac{{200}}{{1000}}} \right) \cdot \left[ {5 - \left( { - 10} \right)} \right]
Δp=(02)(15)\Rightarrow \Delta p = \left( {0 \cdot 2} \right) \cdot \left( {15} \right)
Δp=3Ns\Rightarrow \Delta p = 3Ns
The change in the momentum isΔp=3Ns\Delta p = 3Ns.
The correct answer for this problem is option B.

Note: Momentum is a vector quantity and therefore if there is change in line of motion of the body then we calculate the momentum along the same directions. The velocity of the hockey ball is negative while returning towards its original path.