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Question: A hiker stands on the edge of a cliff 490 m above the ground and throw a stone horizontally with a s...

A hiker stands on the edge of a cliff 490 m above the ground and throw a stone horizontally with a speed of 15 m s-1. The time taken by the stone to reach the ground is

A

5 s

B

10 s

C

12 s

D

15 s

Answer

10 s

Explanation

Solution

Here, u=15ms1,h=490mu = 15ms^{- 1},h = 490m

Time taken by the atone to reach the ground is

t=2hg=2×490m9.8ms1=10st = \sqrt{\frac{2h}{g}} = \sqrt{\frac{2 \times 490m}{9.8ms^{- 1}}} = 10s