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Question

Physics Question on Motion in a plane

A hiker stands on the edge of a cliff 490m490\,m above the ground and throws a stone horizontally with a speed of 15ms115\,ms^{-1}. The time taken by the stone to reach the ground is

A

5s5\,s

B

10s10\,s

C

12s12\,s

D

15s15\,s

Answer

10s10\,s

Explanation

Solution

Here, u=15ms1u = 15\,m \,s^{-1}, h=490mh = 490\,m Time taken by the stone to reach the ground is t=2hgt=\sqrt{\frac{2h}{g}} =2×490m9.8ms2=\sqrt{\frac{2\times490\,m}{9.8\,ms^{-2}}} =10s=10\,s