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Question: A highly rigid cubical block A of small mass M and side L is fixed rigidly on the another cubical bl...

A highly rigid cubical block A of small mass M and side L is fixed rigidly on the another cubical block of same dimensions and of low modulus of rigidity h such that the lower face of A completely covers the upper face of B. The lower face of B is rigidly held on the horizontal surface. A small force F is applied perpendicular to one of the side faces of A. After the force is withdrawn, block A excutes small oscillations, the time period of which is given by –

A

2π(MηL)2\pi\sqrt{(M\eta L)}

B

2π(Mη/L)2\pi\sqrt{(M\eta/L)}

C

2π(ML/η)2\pi\sqrt{(ML/\eta)}

D

2π(M/Lη)2\pi\sqrt{(M/L\eta)}

Answer

2π(M/Lη)2\pi\sqrt{(M/L\eta)}

Explanation

Solution

t[M]a[η]b[L]c\mathrm { t } \propto [ \mathrm { M } ] ^ { \mathrm { a } } [ \eta ] ^ { \mathrm { b } } [ \mathrm { L } ] ^ { \mathrm { c } } M0L0T1M^{0}L^{0}T^{1} \proptoM0L0TMa+bLb+cT2bM^{0}L^{0}T \propto M^{a + b}L^{- b + c}T^{- 2b}

Equating dimensions of both sides.

a + b = 0 ̃ a = –b

–b + c = 0 ̃ b = c

–2b = 1 ̃ b = –1/2

\ a = 1/2, c = –1/2

Therefore t µ M1/2[h]–1/2[L]–1/2

T µ MηL\sqrt{\frac{M}{\eta L}}.