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Question: A highly rigid cubical block A of small mass M and side L is fixed rigidly onto another cubical bloc...

A highly rigid cubical block A of small mass M and side L is fixed rigidly onto another cubical block B of the same dimensions and of low modulus of rigidity η\eta such that the lower face of A completely covers the upper face of B. The lower face of B is rigidly held on a horizontal surface. A small force F is applied perpendicular to one of the side faces of A. After the force is withdrawn block A executes small oscillations. The time period of which is given by

A

2πMηL2\pi\sqrt{\frac{M\eta}{L}}

B

2πLMη2\pi\sqrt{\frac{L}{M\eta}}

C

2πMLη2\pi\sqrt{\frac{ML}{\eta}}

D

2πMηL2\pi\sqrt{\frac{M}{\eta L}}

Answer

2πMηL2\pi\sqrt{\frac{M}{\eta L}}

Explanation

Solution

Given m = mass = [M], η\eta = coefficient of rigidity =

[ML1T2]\lbrack ML^{- 1}T^{- 2}\rbrack, L = length = [L]

By substituting the dimension of these quantity we can check the accuracy of the given formulae

[T]=2π([M][η][L])1/2\lbrack T\rbrack = 2\pi\left( \frac{\lbrack M\rbrack}{\lbrack\eta\rbrack\lbrack L\rbrack} \right)^{1/2}= [MML1T2L]1/2\left\lbrack \frac{M}{ML^{- 1}T^{- 2}L} \right\rbrack^{1/2}= [T].

L.H.S. = R.H.S. i.e., the above formula is Correct**.**