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Question

Physics Question on electrostatic potential and capacitance

A hexagon of side 8cm8 \,cm has a charge 4μC4\,\mu\,C at each of its vertices. The potential at the centre of the hexagon is

A

2.7×106V2.7 \times 10^6\,V

B

7.2×1011V7.2 \times 10^{11}\, V

C

2.5×1012V2.5 \times 10^{12}\, V

D

3.4×104V3.4 \times 10^4 \, V

Answer

2.7×106V2.7 \times 10^6\,V

Explanation

Solution

As shown in the figure, O is the centre of hexagon ABCDEF of each side 8 cm. As it is a regular hexagon OAB, OBC, etc are equilateral triangles. ? OA = OB = OC = OD = OE = OF = 8 cm \quad\quad \quad\quad\quad= 8 ? 10 m The potential at O is V=6×q4πε0rV=6\times\frac{q}{4\pi\varepsilon_{0}r} =6×9×109×4×1068×102=2.7×106V\quad=\frac{6\times9\times10^{9}\times4\times10^{-6}}{8\times10^{-2}}=2.7\times10^{6} V