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Question: A helicopter of mass 2000 kg rises with a vertical acceleration of \(15 \mathrm {~ms} ^ { - 1 }\) 2...

A helicopter of mass 2000 kg rises with a vertical acceleration of 15 ms115 \mathrm {~ms} ^ { - 1 } 2, The total mass of the crew and passengers is 500 kg. Choose the correct statements form the following. (Take g=10 ms2\mathrm { g } = 10 \mathrm {~ms} ^ { - 2 } )

(i) The force on the floor of the helicopter by the crew and passengers is 1.25×104 N1.25 \times 10 ^ { 4 } \mathrm {~N} vertically downwards

(ii) The action of the rotor of the helicopter on the surrounding air is 6.25×1046.25 \times 10 ^ { 4 } vertically downwards

(iii) The force on the helicopter due to the surrounding ai is 6.25×104 N6.25 \times 10 ^ { 4 } \mathrm {~N} vertically upwards

A

(i) and (ii)

B

(ii) and (iii)

C

(i) and (iii)

D

All the three

Answer

All the three

Explanation

Solution

Here

Mass of helicopter, M=2000 kgM = 2000 \mathrm {~kg}

Mass of the crew and passengers, m=500 kgm = 500 \mathrm {~kg}

Vertically upwards acceleration , a=15ms2a = 15 m s ^ { - 2 }

g=10ms2g = 10 m s ^ { - 2 }

(i) Force on the floor by the crew and passengers

=m(g+a)=500 kg(10+15)ms2= m ( g + a ) = 500 \mathrm {~kg} ( 10 + 15 ) \mathrm { ms } ^ { - 2 }

=12500N=1025×104N= 12500 N = 1025 \times 10 ^ { 4 } N

It acts vertically downwards

(ii) Action of the rotor of the helicopter on the surrounding air

=(M+m)(g+a)= ( M + m ) ( g + a ) =(2000+500)kg(10+15)ms2= ( 2000 + 500 ) \mathrm { kg } ( 10 + 15 ) \mathrm { ms } ^ { - 2 } =62500 N=6.25×104 N= 62500 \mathrm {~N} = 6.25 \times 10 ^ { 4 } \mathrm {~N}

It acts vertically downwards

(iii) Force on the helicopter due to the surrounding air is equal and opposite to the action of the rotor of the helicopter on the surrounding air.

\thereforeforce on the helicopter due to the surrounding air

=6.25×104N= 6.25 \times 10 ^ { 4 } N

It acts vertically upwards