Question
Question: A helicopter changes its velocity from \[30{m}/{s}\;\] due to north to \[40{m}/{s}\;\] due east in 2...
A helicopter changes its velocity from 30m/s due to north to 40m/s due east in 20 s. What is the magnitude of average acceleration during this time?
Solution
The average acceleration equals the change in velocity of a body by the time taken by the body. The change in the value of the velocity of the helicopter can be computed by finding the root of the sum of the squares of the initial and final velocity of the helicopter. As the total time taken by the helicopter is known, so, by dividing the change in velocity of the helicopter by the time taken, we can obtain the value of the average acceleration.
Complete step-by-step solution:
From the given information, we have the data as follows.
A helicopter changes its velocity from 30m/s due to north to 40m/s due east in 20 s.
The average acceleration equals the change in velocity of a body by the time taken by the body. The mathematical representation of the same is,
Average acceleration=Time takenChange in velocity
Substitute the values in the above equation.