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Question

Physics Question on Nuclear physics

A heavy nucleus NN, at rest, undergoes fission NP+QN \rightarrow P + Q, where PP and QQ are two lighter nuclei Let δ=MN\delta= M _{ N } - MPMQM_{P}-M_{Q}, where MP,MQM_{P}, M_{Q} and MNM_{N} are the masses of P,QP, Q and NN, respectively EPE _{P} and EQE_{Q} are the kinetic energies of PP and QQ, respectively. The speeds of PP and QQ are vPv_{P} and vQv_{Q}, respectively If cc is the speed of light, which of the following statement(s) is(are) correct?

A

Ep+EQ=c2δE_{p}+E_{Q}=c^{2} \delta

B

Ep=(MpMp+MQ)c2δE_{p}=\left(\frac{M_{p}}{M_{p}+M_{Q}}\right) c^{2} \delta

C

vPvQ=MQMP\frac{ v _{ P }}{ v _{ Q }}=\frac{ M _{ Q }}{ M _{ P }}

D

The magnitude of momentum for PP as well as QQ is c2μδc \sqrt{2 \mu \delta}, where μ=MpMQ(Mp+MQ)\mu=\frac{ M _{ p } M _{ Q }}{\left( M _{ p }+ M _{ Q }\right)}

Answer

The magnitude of momentum for PP as well as QQ is c2μδc \sqrt{2 \mu \delta}, where μ=MpMQ(Mp+MQ)\mu=\frac{ M _{ p } M _{ Q }}{\left( M _{ p }+ M _{ Q }\right)}

Explanation

Solution

D

The magnitude of momentum for PP as well as QQ is c2μδc \sqrt{2 \mu \delta}, where μ=MpMQ(Mp+MQ)\mu=\frac{ M _{ p } M _{ Q }}{\left( M _{ p }+ M _{ Q }\right)}