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Question

Physics Question on Current electricity

A heating element using nichrome connected to a 230 V supply draws an initial current of 3.2 A which settles after a few seconds to a steady value of 2.8 A. What is the steady temperature of the heating element if the room temperature is 27.0 °C? Temperature coefficient of resistance of nichrome averaged over the temperature range involved is 1.70×104°C11.70 × 10^{−4} °C^{ −1}.

Answer

Supply voltage, V=230VV = 230\,V
Initial current drawn, I1=3.2AI_1 = 3.2\,A
Initial resistance = R1R_1, which is given by the relation,
R1=VIR_1 =\frac{ V}{I}
R1=2303.2R_1 = \frac{230}{3.2}
R1=71.87R_1 = 71.87 Ω
Steady state value of the current, I2=2.8AI_2 = 2.8 \,A
Resistance at the steady state = R2R_2, which is given as
R2=2302.8=82.14R_2 = \frac{230}{2.8} = 82.14 \,Ω
Temperature co-efficient of nichrome, α=1.70×104°C1 α = 1.70 × 10^{−4 }°C^{−1}
Initial temperature of nichrome, T1=27.0°CT_1= 27.0 °C
Study state temperature reached by nichrome = T2T_2
T2T_2 can be obtained by the relation for αα,
α=R2R1R1(T2T1)α = \frac{R_2 - R_1}{R_1(T_2-T_1)}
T227°C=82.14×71.8771.87×1.7×104=840.5T_2 - 27 °C = \frac{82.14 \times 71.87}{71.87 \times 1.7 \times 10^{-4} }= 840.5
T2=840.5+27T_2 = 840.5 + 27
T2=867.5°CT_2 = 867.5 °C
Therefore, the steady temperature of the heating element is 867.5°C867.5 °C.