Question

(a) ${H_2 O_2 + O_3 -> H_2O + 2O_2}$ (b) ${H_2 O_2 + Ag_2O -> 2Ag + H_2O + O_2}$ Role of hydrogen peroxide in the above reactions is respectively -

• A. Oxidizing in (a) and reducing in (b)
• B. Reducing in (a) and oxidizing in (b)
• C. Reducing in (a) and (b)
• D. Oxidizing in (a) and (b)

Answer 1

Answer: (C)

Reducing in (a) and (b)

Answer 2

In the reaction,
Since ${{H}_{2}}{{O}_{2}}$
oxidises, ${{O}_{3}}$
into${{O}_{2}}$
,
thus it behaves as an oxidising agent. Further, in the reaction, Here ${{H}_{2}}{{O}_{2}}$
reduces $A{{g}_{2}}O$
into metallic silver [Ag] (as oxidation number is reducing from +1 to 0). Thus, ${{H}_{2}}{{O}_{2}}$
behaves as a reducing agent.