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Question: A gun of mass \(10kg\) fires 4 bullets per second. The mass of each bullet is 20 g and the velocity ...

A gun of mass 10kg10kg fires 4 bullets per second. The mass of each bullet is 20 g and the velocity of the bullet when it leaves the gun is 300ms−1.300ms^{- 1}. The force required to hold the gun while firing is

A

6 N

B

8 N

C

24 N

D

240 N

Answer

24 N

Explanation

Solution

Rate of change of momentum of the bullet in forward direction = Force required to hold the gun.

F=nmv=4×20×10−3×300=24NF = nmv = 4 \times 20 \times 10^{- 3} \times 300 = 24N