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Question

Physics Question on laws of motion

A gun of mass 10 kg fires 4 bullets per second. The mass of each bullet is 20 g and the velocity of the bullet when it leaves the gun is 300 ms. The force required to hold the gun when firing is

A

6 N

B

8 N

C

24 N

D

240 N

Answer

24 N

Explanation

Solution

Momentum of one bullet, p = mv = 20 ? 103^{-3} ? 300 = 6 kg m s1^{-1} N = number of bullet per sec = 4 ?dpdt=? \frac{dp}{dt}= change of momentum per sec or force \quad \quad \quad= N(p - 0) = 4 ? 6 = 24 N