Question
Physics Question on laws of motion
A gun of mass 10 kg fires 4 bullets per second. The mass of each bullet is 20 g and the velocity of the bullet when it leaves the gun is 300 ms. The force required to hold the gun when firing is
A
6 N
B
8 N
C
24 N
D
240 N
Answer
24 N
Explanation
Solution
Momentum of one bullet, p = mv = 20 ? 10−3 ? 300 = 6 kg m s−1 N = number of bullet per sec = 4 ?dtdp= change of momentum per sec or force = N(p - 0) = 4 ? 6 = 24 N