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Question: A group of \(10\) items has an arithmetic mean of \(6\), if the arithmetic mean of \(4\) of those it...

A group of 1010 items has an arithmetic mean of 66, if the arithmetic mean of 44 of those items is 7.57.5. Then what is the meaning of the remaining elements?
(A) 6.5{\text{(A) 6}}{\text{.5}}
(B) 5.5{\text{(B) 5}}{\text{.5}}
(C) 4.5{\text{(C) 4}}{\text{.5}}
(D) 5.0{\text{(D) 5}}{\text{.0}}

Explanation

Solution

Here we have to find the mean of the remaining elements. By using the data, we can find the sums of the items are 1010 and 44 by using the formula. Then we find the total number of items and sum of the item. Finally we use the formula and find the required answer.

Formula used: Mean=Sum of termsnumber of termsMean = \dfrac{{{\text{Sum of terms}}}}{{{\text{number of terms}}}}

Complete step-by-step solution:
It is given that the question stated as the mean of all the terms is 66 and since there are total 1010 terms in the distribution, using the formula of mean we can write it as:
6=Sum of terms10\Rightarrow 6 = \dfrac{{{\text{Sum of terms}}}}{{10}}
On cross multiplying the equation, we get:
6×10=Sum of terms\Rightarrow 6 \times 10 = {\text{Sum of terms}}
On simplifying we get:
60=Sum of terms\Rightarrow 60 = {\text{Sum of terms}}
Therefore, we know the sum of all the 1010 terms in the distribution is 6060
Also, the mean of the any 44 numbers from the distribution is 7.57.5 therefore, using the formula of mean we can write it as:
7.5=Sum of terms4\Rightarrow 7.5 = \dfrac{{{\text{Sum of terms}}}}{4}
On cross multiplying the above equation, we get:
7.5×4=Sum of terms\Rightarrow 7.5 \times 4 = {\text{Sum of terms}}
On simplifying we get:
30=Sum of terms\Rightarrow 30 = {\text{Sum of terms}}
Therefore, we know the sum of all the 44 terms in the distribution is 3030.
Now since there are total 1010 terms in the distribution which have a sum of 6060 out of which we know the sum of terms of 44 terms is 3030 therefore the sum of the remaining terms is:
=6030= 60 - 30
On simplifying we get:
Sum of the terms=30 = 30
Now since we subtracted the sum of 44 terms from the total number of terms, the remaining numbers of terms are:
=104= 10 - 4
On simplifying we get:
Number of terms=6 = 6
Therefore, we have to use the formula of mean, the mean of the remaining terms in the distribution is:
Mean=306Mean = \dfrac{{30}}{6}
On dividing the terms we get:
Mean=5Mean = 5, which is the required answer.

Therefore, the correct option is (D)(D).

Note: Mean is the most commonly used measure of central tendency and it is usually considered to be the measure of it. Mean should not be used when the data is non-numeric or when there are extreme values in the distribution.
Mode is to be used when the given distribution is nominal, which implies that the class or category is not based on numbers for example: city, age, gender etc.