Question
Question: A grinding wheel attained a velocity of \[20rad/sec\] in \[5sec\] starting from rest. Find the numbe...
A grinding wheel attained a velocity of 20rad/sec in 5sec starting from rest. Find the number of revolutions made by the wheel.
A. 25π revolutions per second
B. π1 revolutions per second
C. π25 revolutions
D. None
Solution
We know about linear motion, when some force is applied to an object it starts moving. Similarly, we have rotational motion. When we fix one end of the object then it cannot move from its place but can only rotate. The force applied here is called torque.
Complete step by step answer:
Let us first write the information given in the question.
Initial velocity ω0=0, velocity attained ω=20rad/sec, time = 5sec.
We have to calculate the number of revolutions made by the wheel.
We have the following equation of motion.
ω0−ω=αt
Where, ω0 is the initial angular velocity, ωis the final angular velocity, α is the angular acceleration and t is the time.
Let us first calculate the angular acceleration using the above equation of motion.
α=50−20=−4rad/s2
A negative sign shows the deceleration, i.e., acceleration is working opposite to the direction of motion.
Let us find the angular displacement using the following equation of motion.
θ=ω0t+21αt2
Here θis the displacement and other terms have their usual meaning.
Let us substitute the values.
θ=0×5+21×4×(5)2⇒θ=50rad
Now, we know one revolution will be done when 2π radian is completed. So, to calculate the number of revolutions we will divide the angular displacement with 2πradian.
Number of revolutions = 2π50=π25
So, the correct answer is “Option C”.
Note:
All the laws of motion which are applicable in linear motion are also applicable in rotational motion.
Rotational analogs of velocity are angular velocity, inertia is a moment of inertia, acceleration is angular acceleration and displacement is angular displacement.