Question

A graph plotted between log t50% vs. log concentration is a straight line. What conclusion can you draw from this graph.

• A. $\mathrm { n } = 1 ; \mathrm { t } _ { 1 / 2 } \propto \mathrm { a }$
• B. $\text{n = 2, }\text{t}_{\text{1/2}} \propto \text{1/a}$
• C. $\text{n = 1 ; }\text{t}_{\text{1/2}}\text{ = }(\text{0.693 / k})$
• D. None of these

Answer 1

Answer: (C)

$\text{n = 1 ; }\text{t}_{\text{1/2}}\text{ = }(\text{0.693 / k})$

Answer 2

As t_50% is constant. Hence order of reaction is 1.

$t_{50\%} = \frac{0.693}{K}$

$n = 1,t_{1/2} = \frac{0.693}{K}$