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Question

Physics Question on Motion in a straight line

A goods train accelerating uniformly on a straight railway track, approaches an electric pole standing on the side of track. Its engine passes the pole with velocity uu and the guard?s room passes with velocity vv. The middle wagon of the train passes the pole with a velocity.

A

u+v2\frac{u+v}{2}

B

12u2+v2\frac{1}{2}\sqrt{u^{2}+v^{2}}

C

uv\sqrt{uv}

D

(u2+v22)\sqrt{\left(\frac{u^{2}+v^{2}}{2}\right)}

Answer

(u2+v22)\sqrt{\left(\frac{u^{2}+v^{2}}{2}\right)}

Explanation

Solution

Let S'S' be the distance between two ends a'a' be the constant acceleration As we know V2u2=2aSV^2 - u^2 = 2aS or, aS=V2u22aS=\frac{V^{2}-u^{2}}{2} Let VV be velocity at mid point. Therefore, Vc2u2=2aS2V^{2}_{c}-u^{2}=2a \frac{S}{2} Vc2=u2+aSV^{2}_{c}=u^{2}+aS Vc2=u2+V2u22V^{2}_{c}=u^{2}+\frac{V^{2}-u^{2}}{2} Vc=u2+v22V_{c}=\sqrt{\frac{u^{2}+v^{2}}{2}}