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Question: A glass tube of 1.0 m length is filled with water. The water can be drained out slowly at the bottom...

A glass tube of 1.0 m length is filled with water. The water can be drained out slowly at the bottom of the tube. If a vibrating tuning fork of frequency 500 Hz is brought at the upper end of the tube and the velocity of sound is 330 m s–1, then the total number of resonances obtained will be

A

4

B

3

C

2

D

1

Answer

3

Explanation

Solution

Wavelength,

λ=VelocityFrequency=330ms1500s1=0.66m\lambda = \frac{Velocity}{Frequency} = \frac{330ms^{- 1}}{500s^{- 1}} = 0.66m

The resonance occurs at

λ4,3λ4,5λ4,7λ4,......\frac{\lambda}{4},\frac{3\lambda}{4},\frac{5\lambda}{4},\frac{7\lambda}{4},......

i.e., at 0.1650.165m 0.4950.495m, 0.8250.825m, 1.155m1.155mAs the length of the tube is only 1.0m1.0m, hence 3 resonances will be observed.