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Question: A glass of juice contains \( {{9 gm}} \) of glucose. How many atoms of each kind are there in the gl...

A glass of juice contains 9gm{{9 gm}} of glucose. How many atoms of each kind are there in the glass of juice?

Explanation

Solution

We know one mole of any compound or element contain 6.02×1023{{6}}{{.02 \times 1}}{{{0}}^{{{23}}}} molecules or atoms respectively. So we calculate the number of moles present in 9g{{9 g}} of glucose and find out the number of atoms present in the total weight of the glucose.

Complete answer:

Glucose molecule formula - C6H12O6{{{C}}_{{6}}}{{H}}{ _{{{12}}}}{{{O}}_{{6}}}

Molar mass of carbon = 12.01g/mol{{12}}{{.01 g/mol}}

Molar mass of hydrogen = 1.008g/mol{{1}}{{.008 g/mol}}

Molar mass of oxygen = 16.0g/mol{{16}}{{.0 g/mol}}

Molecularmassofglucose=6(12.01)+12(1.008)+6(16.0){{Molecular mass of glucose = 6(12}}{{.01) + 12(1}}{{.008) + 6(16}}{{.0)}}

=72.06+12.096+96= 72.06 + 12.096 + 96

=180.156g/mol180g/mol{{ = 180}}{{.156 g/mol }} \approx {{180 g/mol}}

One mole of glucose contains 6.02×10236.02 \times {10^{23}} atoms.

Molecular mass of C6H12O6=180g/mol{{{C}}_{{6}}}{{{H}}_{{{12}}}}{{{O}}_{{6}}}{{ = 180 g/mol}}

9g{{9 g}} of C6H12O6{{{C}}_{{6}}}{{{H}}_{{{12}}}}{{{O}}_{{6}}} =?

Numberofmoleculesin9gofC6H12O6=9×6.023×1023180=3.01×1022molecules{{Number of molecules in 9g of }}{{{C}}_{{6}}}{{{H}}_{{{12}}}}{{{O}}_{{6}}}{{ = }}\dfrac{{{{9 \times 6}}{{.023 \times 1}}{{{0}}^{{{23}}}}}}{{{{180}}}}{{ = 3}}{{.01 \times 1}}{{{0}}^{{{22}}}}{{ molecules}}

Let’s calculate the number of each atom in nine grams of glucose.

Carbon atoms:

Number  of  carbon  atoms  in  9g  of  glucose=6×3.01×1022=18.06×1022{{Number\; of\; carbon\; atoms \; in \; 9g \; of\; glucose = 6 \times 3}}{{.01 \times 1}}{{{0}}^{{{22 }}}}{{ = 18}}{{.06 \times 1}}{{{0}}^{{{22}}}}

Hence, 18.06×1022{{18}}{{.06 \times 1}}{{{0}}^{{{22}}}} of carbon atoms present in the 9g{{9g}} of glucose.

Oxygen atoms:

Number  of  oxygen  atoms  in  9g  of  glucose=6×3.01×1022=18.06×1022{{Number\; of \; oxygen\; atoms\; in \; 9g \; of \; glucose = 6 \times 3}}{{.01 \times 1}}{{{0}}^{{{22 }}}}{{ = 18}}{{.06 \times 1}}{{{0}}^{{{22}}}}

Hence, 18.06×1022{{18}}{{.06 \times 1}}{{{0}}^{{{22}}}} of oxygen atoms present in the 9g{{9g}} of glucose.

Hydrogen atoms:

Number  of  hydrogen  atoms  in  9g  of  glucose=12×3.01×1022=36.12×1022{{Number\; of\; hydrogen\; atoms \; in \; 9g \; of \; glucose = 12 \times 3}}{{.01 \times 1}}{{{0}}^{{{22 }}}}{{ = 36}}{{.12 \times 1}}{{{0}}^{{{22}}}}

Hence, 36.12×1022{{36}}{{.12 \times 1}}{{{0}}^{{{22}}}} of hydrogen atoms present in the 9g{{9g}} of glucose.

Additional Information:

Moles are the number of molecular mass units present in a particular weight of that compound.

in chemistry it is very less likely we deal with single atom or single molecule so the concept of mole is very important and we can easily relate moles with atoms or molecules by formula that 1mole{{1 mole}} contain Avogadro number of molecule i.e. 6.02×1023atoms{{6}}{{.02 \times 1}}{{{0}}^{{{23}}}}{{ atoms}} .

The Avogadro value is a constant value for every element and compound. Avogadro number informs us about the number of molecules or atoms or electrons present in the bulk of the solution.

Note: We should pay special attention to the units of the molar masses used. The most frequently used unit s g/mol which is also the standard value and gives an exact answer in the standard unit system. We should avoid using values of unit kg/mol or a.m.u.