Question

A glass flask of volume one litre at 0⁰C is filled, level full of mercury at this temperature. The flask and mercury are now heated to 100⁰C. How much mercury will spill out, if coefficient of volume expansion of mercury is $1.82 \times 10^{- 4} ⥂ /{^\circ}C$ and linear expansion of glass is $0.1 \times 10^{- 4} ⥂ /{^\circ}C$ respectively

• A. 21.2 cc
• B. 15.2 cc
• C. 1.52 cc
• D. 2.12 cc

Answer 1

Answer: (C)

1.52 cc

Answer 2

Due to volume expansion of both liquid and vessel, the change in volume of liquid relative to container is given by ∆V = $V\lbrack\gamma_{L} - \gamma_{S}\rbrack\Delta\theta$

Given V = 1000 cc, α_g = 0.1×10^–4/°C

∴ $\gamma_{g} = 3\alpha_{g} = 3 \times 0.1 \times 10^{- 4}/{^\circ}C = 0.3 \times 10^{- 4}/{^\circ}C$

∴ ∆V = 1000 [1.82 × 10^–4 – 0.3 × 10^–4] × 100 = 15.2 cc